The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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Answer:
768 m²
Step-by-step explanation:
8 x 400 = 3200 cm = 32 m
6 x 400 = 2400 cm = 24m
32 x 24 = 768 m²
Collect like terms (x + 7x) + (-1 + 4 - 3)
Simplify
Answer: 8x
Answer:
$42.83
Step-by-step explanation:
1: Subtract the amount they have by the amount they need.
1328-43= $1,285.
2: Divide amount they need ($1,285) by the total staff members (30). Hence the equation is 1285 ÷ 30
3: Whatever answer you get from that equation is the answer
1285 ÷ 30 = $42.83
When you divide, you are setting the amount each staff member needs to donate by seeing how much money 30 people can give (equally) that adds up to 1285.
Hope this helps :)
-jp524
Enrolement increased by 30% that means last year=100%
incease of 30%=30+100=130% now
now=182
percent means parts out of 100 so
130%=130/100=13/10
182=13/10 of x (x represents the number last year)
of means multipy so
182=13/10 times x
multiply both sides by 10/13 to clear fraction
182 times 10/13=x=140
140 students last year