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hoa [83]
3 years ago
14

Please tell me if my answers are right

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0
Yeah I’m PREETY sure
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PLEASE HELP ME!!!!! Factor completely b^4 − b^3 + b − 1
Afina-wow [57]
<span>b^4 − b^3 + b − 1
=(</span><span>b^4 − b^3) + (b − 1)
= b^3(b - 1) + (b - 1)
=(b - 1)(b^3 + 1)</span>
7 0
3 years ago
NOT GRADED. <br>FIND THE MEASURE OF THE INDICATED ANGLE IN EACH TRIANGLE.​
Setler [38]

Answer:

The angle in the box is always 50 and that other acute angle is 46

Hope this helps

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find f(x) and g(x) so that the function can be described as y = f(g(x)).<br><br> y = 4/x^2+9
dlinn [17]

I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,

One possible answer is f(x) = \frac{4}{x},  \ \ g(x) = x^2+9

Another possible answer is f(x) = \frac{4}{x+9}, \ \ g(x) = x^2

There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)

So in the first example above, we would have

f(x) = \frac{4}{x}\\\\f( g(x) ) = \frac{4}{g(x)}\\\\f( g(x) ) = \frac{4}{x^2+9}

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.

Similar steps will happen with the second example as well (when g(x) = x^2)

4 0
3 years ago
Why did I get this question wrong?
lord [1]

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

If u = -rt/V, then du = -r/V dt.

∫ -C₀ e^u du

-C₀ ∫ e^u du

-C₀ e^u + C

-C₀ e^(-rt/V) + C

Evaluate between t=0 and t=30.

-C₀ e^(-30r/V) − -C₀ e^(-0r/V)

-C₀ e^(-30r/V) + C₀

C₀ (-e^(-30r/V) + 1)

I got the same answer.  Try changing the lowercase v to an uppercase V.

4 0
3 years ago
I will give brainliest if anyone answers this : Would you like to be my friend on brainly? :)
Artyom0805 [142]

Answer:

alr then bet

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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