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3 years ago

Find the area of the patio

Mathematics

1 answer:

DIA [1.3K]3 years ago

7 0

Answer:19x^2-68x

Step-by-step explanation:

first, add the 2x on the side of the large rectangle to the 2x on the pool side to find the length. then find the area of the entire image (4x•8x-10=32x^2-40x) now find the area of the pool (2x•6x-14=12x^2-28x) and add it to the area of the hot tub (x•x=x^2) (13x^2-28x) finally subtract that from the area of the entire image (32x^2-40x=19x^2-68x)!

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Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta

Irina-Kira [14]

Answer:

The inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

Step-by-step explanation:

The inner function is the one we apply the outer function to.

$y = \tan{\pi x}$

We apply the outer function tangent to $\pi x$ .

So, the inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

The derivative of a compositve function

$y = f(u)$ in which $u = g(x)$ is given by the following function.

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$f(u) = \tan{u}$

$f^{\prime}(u) = \sec^{2}{u}$

$u = g(x) = \pi x$

$g^{\prime}(x) = \pi$

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

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3 years ago

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Step-by-step explanation:

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