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3 years ago

Given: tangent to Circle O. If m C = 57°, then m BDR =

1 answer:

8 0

∠BCD = 57°
∴ ∠BDR = ∠BCD = 57° (angle that meets the chord and the tangent is equi-angular to the angle at the alternate segment)

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6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago

Please help me thanks please Will give you brainlest

Akimi4 [234]

Answer:

224

Step-by-step explanation:

Base:

A = Bh

A = 8(8) = 64

Sides:

A = 1/2 Bh

A = 1/2 8(10)

A = 40

Then you do 40(4) because there are 4 sides:

40 (4) = 160

Then you add up the base and the sides:

160 + 64 = 224

(I think this is the right answer)

7 0

3 years ago

A student desk measures 1.5 meters. The dry erase board measures 3.5 meters. How much longer is the dry erase board than the des

Serga [27]

The dry erase board is 200 centimeters longer.

4 0

3 years ago

Read 2 more answers

PLS HELP THIS IS HARD ANYONE PLS

Valentin [98]

This question is very oddly worded. The domain is the set of x-values, but this is a set of (x,y) ordered pairs.

I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }. If this is reflected over the x-axis, what's the range?"

Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.

(1,5) -> (1,–5)

(2,1) -> (2,–1)

(-1,-7) -> (-1,+7)

I'd pick the third option.

6 0

3 years ago

Finding Derivatives Implicity In Exercise, find dy/dx implicity. 4x3 + ln y2 + 2y = 2x

lisov135 [29]

Answer:

$\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}$

Step-by-step explanation:

Given function : 4x³ + ln(y²) + 2y = 2x

on differentiating both sides with respect to 'x', we get

$\frac{d(4x^3 + ln(y^2) + 2y)}{dx}= \frac{d(2x)}{dx}$

$12x^2+\frac{2}{y}(\frac{dy}{dx})+2(\frac{dy}{dx})=2$

$12x^2+(\frac{2}{y}+2)\frac{dy}{dx}=2$

$(\frac{2+2y}{y})\frac{dy}{dx}=2-12x^2$

$\frac{dy}{dx}=\frac{y(2-12x^2)}{2+2y}$

$\frac{dy}{dx}=\frac{2y(1-6x^2)}{2(1+y)}$

$\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}$

3 0

3 years ago