A fair coin is tossed .if the coin is tails one die is rolled and the number on the die is recorded if the coin toss is heads tw
o die are rolled and the sum of the numbers on two independent fair dice is recorded
Whaat is the probability the result is 9?
1 answer:
So for the dice to be 9 two die must be rolled. So we start with a 1/2 chance.
Then there are 36 possibilities to be rolled on a die (6*6) and there are 4/36 possibilities for the dice to roll a 9 (4+5, 5+4, 3+6, 6+3).
So we multiply 1/2 by 1/9 (4/36)- which equals 1/18.
So there is a 1/18 chance for the result of the dice rolled to be a 9.
I hope this helps!
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Answer:
y = 8(x-5)^2 -232
Step-by-step explanation:
Factor out the 8 to get
y = 8(x^2-10x-4)
y = 8(x-5)^2 -232
Answer:
the answer is -32t + 67
Step-by-step explanation:
-16t2 +64 + 3
= -16t x 2 +64 +3
= -32t +67
6/3 = 6 divided by 3
= 2
12/6= 12 divided by 6
= 2
So sum the prime factors up
25=5*5, 5+5=10
26=2*13, 2+13=15
27=3*3*3, 3+3+3=9
15>10>9
26 is biggest
pick 26