<span>Since
this is an SAT Math Level 2 problem derivatives should not be required
to find the solution. To find "How many more hours of daylight does the
day with max sunlight have than May 1," all you need to understand is
that sin(x) has a maximum value of 1.
The day with max sunlight will occur when sin(2*pi*t/365) = 1, giving the max sunlight to be 35/3 + 7/3 = 14 hours
Evaluating your equation for sunlight when t = 41, May 1 will have about 13.18 hours of sunlight.
The difference is about 0.82 hours of sunlight.
Even though it is unnecessary for this problem, finding the actual max
sunlight day can be done by solving for t when d = 14, of by the use of
calculus. Common min/max problems on the SAT Math Level 2 involve sin
and cos, which both have min values of -1 and max values of 1, and also
polynomial functions with only even powered variables or variable
expressions, which have a min/max when the variable or variable
expression equals 0.
For example, f(x) = (x-2)^4 + 4 will have a min value of 4 when x = 2. Hope this helps</span>
1.6 is let's say one pie and 6/10 of a pie and that's how much a baker made which is obviously more that 1 pie and 3/10 of a pie that the baker made.
A process for that is
1.6 =1 6/10 = 16/10 and if u cross multiply that by
1.3 = 1 3/10= 13/10 the value in the 16/10 side will be 160 which is more that the value on the 13/10 side which is 130
27.71 is the sum
pls mark me the brainiest
hope i helped
The answer to A. is 108cm or 1.08m
First convert 2m to cm:
2m x 100 = 200 cm
Next convert 6m to cm:
6m x 100 = 600 cm
Divide the height of the person by his/her shadow:
200cm ÷ 600cm = <span>0.33333333333 = .3</span>
Multiply 360cm by .3:
360cm x .3 = 108cm
108cm ÷ 100 = 1.08m
The answer to B. is 6.8 cm.
The scale seems a bit small... are you sure you don't mean 0.8 m?
a = length of actual car.
8.5 x 0.8 = 1 x a
6.8 = 1 x a
6.8 ÷ 1 = a
6.8 = a
If you did mean 0.8 m... the answer is 680 cm or 6.8 m.
a = length of actual car.
0.8m x 100 = 80cm
8.5 x 80 = 1 x a
680 = 1 x a
680 ÷ 1 = a
680 = a
680 ÷ 100 = 6.8
<span>angle A + angle B = 180 degrees ... rhombus and h is the perpendicular distance between two parallelsides of the rhombus. ... The side length of the rhombus is equal to 10 feet. Find its area. ... A rhombus has 2 congruent opposite acute angles and two congruent ... area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)</span>
