Newton's law of universal gravitation gives the gravitational force between two objects:
F = GMm/r²
F = gravitational force, G = gravitational constant, M & m are the masses of the two objects, r = distance between the objects
The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
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Answer:
A
Explanation:
It will increase cause the more branches you add the total current will increase
The final momentum of the system would be 6680 Kg m/s
<h3>What is momentum?</h3>
It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
Two cars are driving toward each other in a straight line. Car A is 1400 kg and driving at 11 m/s. Car B is 1090 kg and driving at 8 m/s. If the two cars collide inelastically, As we know that the momentum of a system is conserved during the collision
initial momentum = final momentum
the initial momentum of the system = 1400 ×11 + 1090×(-8)
= 6680 Kg m/s
The final momentum of the system = 6680 Kg m/s
Thus,The final momentum of the system would be 6680 Kg m/s
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