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Anestetic [448]
3 years ago
13

Most metals are good electrical conductors because (5 points) they hold their electrons they have a large amount of free electro

ns they are extremely dense the molecules are far apart from each other
Physics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

  • Metals are good conductors of electricity <u>because they have free electrons</u> which help in the transfer of charge from one point to another.

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What is the female sex cells of a plant called?<br> Please help! Tysm!
xz_007 [3.2K]
I thought plants were A-sexual
3 0
3 years ago
The speed of light in a vacuum is 3 x 108 miles/hour. true/false?
GarryVolchara [31]
I'm guessing they rounded because it is technically 2.998 X 108 miles/hour

so I would go with true!
8 0
3 years ago
Read 2 more answers
When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries?
Ket [755]

Answer:

Explanation:

Assume that a single baby cries at X db

4 babies crying would be X + 10log₁₀(4) = X + 6 db

8 0
2 years ago
A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi
Darina [25.2K]

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

Height of the centre of gravity h= 0.5m

Acceleration due to gravity g= 9.8m/s

The potential energy of the body for each step is;

P.E = mgh

P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W

5 0
3 years ago
if you drop a stone from height of 2.5m. what is the speed of the stone right before it hits the ground?
KonstantinChe [14]
Since the stone was dropped from height, its initial velocity = 0 m/s

Using  v² = u² + 2gs.

Where g ≈ 10 m/s²,  u = initial velocity = 0 m/s, s = height from drop = 2.5 m

v² = u² + 2gs

v² = 0² + 2*10*2.5

v² = 0 + 50

v² = 50

v = √50

v ≈ 7.07 m/s

Hence velocity just before hitting the ground is ≈ 7.07 m/s 
6 0
2 years ago
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