The top triangle has a vertical leg of "x", an angle opposed of 18 degrees, and a horizontal leg of d.
So tan (18) = x/d
and d = x/tan (18)
The bottom triangle has a vertical leg of "35-x", an angle opposite of 14 deg.and a horizontal leg of "d".
So tan (14) = (35-x)/d and d = (35-x)/tan (14)
Solving for "d":
x / tan(18) = (35-x)/tan14
(tan14)x = 35tan18-(tan18)x
x (tan14 + tan18) = 35tan18
x = 11.3722/0.5742
x = 19.81 ft. (distance the lady is from the pole)
To know where they’re heading to
lets assume
L = length of the object = 5 cm
h = height of the object = 3 cm
w = width of the object = 2 cm
V = Volume of the object
Since the dimensions of object suggest it to be a cuboid
Volume of the object is given as
V = L w h
inserting the values
V = 5 x 3 x 2
V = 30 cm³
m = mass of the object given = 10 g
ρ = density of the object = ?
density of the object is given as
density of object = mass of object / Volume of object
ρ = m/V
inserting the values
ρ = 10/30
ρ = 0.33 g/cm³
Answer:
-3802 m/s
Explanation:
The y-component of the final velocity is ...
(6598 m/s)·sin(-20.5°) ≈ -2310.7 m/s
The y-component of the velocity due to acceleration is ...
(5200 m/s²)(0.350 s)sin(55°) ≈ 1490.9 m/s
Then the initial velocity in the y-direction is found from ...
initial velocity + change in velocity = final velocity
initial velocity = (final velocity) - (change in velocity)
= -2310.7 m/s - 1490.9 m/s ≈ -3802 m/s
Answer:
1. The frequency of the incident light must be equal to or greater than the threshold frequency of the photons before emission could take place.
2. The intensity of the incident light is proportional to the amount of photons released. The higher the intensity of light, the greater the amount of photons ejected.
Explanation:
1. Photoelectric effect is the process by which light with sufficient frequency falls on the surface of a material, e.g metal, to emit electrons. The incident light must have a minimum value of required frequency for the electrons to be ejected. This energy is termed work function which is a function of frequency.
So for emission to take place, the frequency of the incident light must be equal to or greater than the threshold frequency of the photons.
2. The intensity of light is a measure of the amount of light per unit area. When the intensity of incident light increases, the probability that photons would be released increases. The intensity of the incident light is proportional to the amount of photons released.