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posledela
4 years ago
10

How do electromagnetic waves differ from mechanical waves?

Physics
1 answer:
stich3 [128]4 years ago
6 0

They don't require a medium to propagate, meaning that they can travel through air, solid objects, and space.

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The graph below shows the speed of a car as it drives along a racetrack.
nordsb [41]

Answer:

Average speed = distance/time

From 1 to 9 seconds:

Distance covered = 1 - 0.2 = 0.8 km

Time = 9 - 1 = 8 sec

Average speed = 0.8 km / 8 sec

Average speed = 0.1 km/s .

The average speed for the whole test is 1.6 km / 20 sec = 0.08 km/sec. A graph of speed vs time would average out as a horizontal line at 0.08 km/sec from 1 sec to 21 sec. The area under it would be (0.08 km/s) x (20 sec) = 1.6 km.

Surprise surprise ! The area under a speed/time graph is the distance covered during that time !

In closing, I want to express my gratitude for the gracious bounty of 3 points with which I have been showered. Moreover, the green breadcrust and tepid cloudy water have also been refreshing.

Explanation:

4 0
3 years ago
The voltage in a battery is 9 volts. The resistance is 3 ohms. What is the current? USE CORRECT UNITS!
chubhunter [2.5K]

Answer: Lol “USE CORRECT UNITS!” I GOT YOU BABES: 9/3=3 current is 3 amperes.

Explanation:

3 0
3 years ago
Melanie completes a long distance run at an average speed of 6 mph. If it takes her 3 hours, how far did she run?
Rama09 [41]

Answer:

18 miles

Explanation:

The average speed is 6 mph

Melanie ran for 3 hours

Speed × Time = Distance

So, 6 mph × 3 h = 18 miles

6 0
4 years ago
The 6 kg block is then released and accelerates to the right, toward the 4 kg block. The surface is rough and the coefficient of
KatRina [158]

Answer:

v =3.41 m/s

Explanation:

given,

mass of block 1 = 6 Kg

mass of another block 2 = 4 Kg

coefficient of friction = 0.3

Assuming 6 Kg block is attached to the spring of spring constant 350 N/m

and distance between the two block is equal to 0.5 m

using formula

U = \dfrac{1}{2}kx^2

U = \dfrac{1}{2}\times 350 \times 0.5^2

   U = 43.75 J

using conservation of energy

 KE = U - f.d

where f is the frictional force acting

\dfrac{1}{2}mv^2 = 43.75- \mu m g d

\dfrac{1}{2}\times 6 \times v^2 = 43.75- 0.3\times 6 \times 9.8 \times 0.5

v= \sqrt{11.643}

       v =3.41 m/s

4 0
3 years ago
Non examples of gravity ?
Afina-wow [57]
Floating. When you have no gravity you have nothing to be pushing you down to the floor so that would be an example of no gravity pushing on you.
3 0
3 years ago
Read 2 more answers
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