Answer:
L=31.9 mm
δ = 0.22 mm
Explanation:
Given that
v= 14 m/s
ρ=997 kg/m³
μ= 0.891 × 10⁻3 kg/m·s
As we know that when Reynolds number grater than 5 x 10⁵ then flow will become turbulent.



L=0.0319 m
L=31.9 mm
The thickness of the boundary layer at that location L given as


δ = 0.00022 m
δ = 0.22 mm
Answer:
d) precipitation
Hope it helps you
And if you want to, pls mark it as the brainliest answer
Answer:
Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.
Explanation:
For the rod 1 the angular acceleration is
Similarly, for rod 2

Now, the moment of inertia for rod 1 is
,
and the torque acting on it is (about the center of mass)

therefore, the angular acceleration of rod 1 is


Now, for rod 2 the moment of inertia is


and the torque acting is (about the center of mass)


therefore, the angular acceleration
is


We see here that

therefore

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.
Answer:3.33x10^(-17)
Explanation:
Period=wavelength ➗ velocity
Period=1/10^8 ➗ (3x10^8)
Period=3.33x10^(-17)
Answer:
The terminal velocity is equal to C.
Explanation:
Making the assumption that k and t are positive, we then have that -kt is negative. The value of e^(-kt) will be equal to 1/(e^(kt))
If t increases, e^(kt) will increase exponentially and its reciprocal 1/(e^(kt)) will approach zero.
So, we have:
v(t) = C*(1-0)
v(t) = C*(1)
v(t) = C
Therefore, C is the terminal velocity.