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3 years ago

56+64 GCF Ladder methoud

Mathematics

1 answer:

pogonyaev3 years ago

4 0

The answer is 120 gcf ladder methoud

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A=5x+20

kirza4 [7]

Answer:

video rum is eryn rice of a local food store to the point of the lord and of a man of his name poltergeist and the lord God is the lord God is not in the land and he is the lord of Israel as he will be the

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3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

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2 years ago

Mr. Martin bought a microwave that was originally priced $225. He received a 30% discount. What is the sale price of the microwa

maw [93]

I have a simple but slightly time consuming way of doing this. Find 30% of 100 double it and then find 30% of 25, add the two together... In this case 60 + 7.5. After you do that subtract that number from 225. So subtract 67.5 from 225 and there is your answer. Your answer is 157.5

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2 years ago

Use the triangles to write a congruence statement.

kondor19780726 [428]

Triangle ABC is congruent to triangle MNC by SSS, AAA or AA .....!!

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3 years ago

Hello, can you help me with a probability question, please:)

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2 years ago