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NARA [144]
3 years ago
15

Your goal this week is to be online for a mean of only 60 minutes per day. For the first six days of the week, you are online 70

, 60, 65, 40, 78, and 62 minutes. What is the most time you can be online on the seventh day and still reach your goal?
Mathematics
2 answers:
ipn [44]3 years ago
7 0

Answer: The most time you can be online on the seventh day is 45 hours.

Step-by-step explanation:

Hi, to answer this question we have to obtain the whole week number by multiplying the mean (60) by the seven days of the week:

Mathematically speaking:

  • 60 x 7 = 420 hours

Now, we have to sum the amount of hours online of each day:

  • 70+60+65+40+78+62 =375

Finally, we have to subtract that number to the whole week number:

  • 420 -375 =45 hours

The most time you can be online on the seventh day is 45 hours.

8_murik_8 [283]3 years ago
4 0
60*7=420
70+60+65+40+78+62=375
420-375=45
You can only be online for 45 minutes on the seventh day to reach your goal
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Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160
s344n2d4d5 [400]

Answer:

C. 130^{\circ}

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40^o, arc AB = 60^o, and arc BC = 160^o. We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.    

\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}

Let us find measure of arc AD by subtracting measure of given arcs from 360 degrees as:

\widehat{AD}=360^{\circ}-(60^{\circ}+40^{\circ}+160^{\circ})

\widehat{AD}=360^{\circ}-(260^{\circ})

\widehat{AD}=100^{\circ}

\angle AED=\frac{160^{\circ}+100^{\circ}}{2}

\angle AED=\frac{260^{\circ}}{2}

\angle AED=130^{\circ}

Therefore, measure of angle AED is 130 degrees and option C is the correct choice.

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Step-by-step explanation:

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Step-by-step explanation:

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