All categories

3 years ago

How do i solve this? Please help me and show work

Mathematics

1 answer:

Charra [1.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

x^2+8x-6=0

(x^2+8x+16) -6=0+16

(x+4)^2-6=16

(x+4)^2=22

x+4= sqaure root of 22

x= -4 + or minus sqaure root 22

You might be interested in

31*20 hey can u help me solve this problem for me. <img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" "

timurjin [86]

31×20. it equals 620.

6 0

3 years ago

What is the simplified expression for -3cd-d(2c-4)-4d

kodGreya [7K]

Answer:

-5cd

Step-by-step explanation:

-3cd-d(2c-4)-4d

Distribute the -d

-3cd-d2c-+d4-4d

-3cd -2cd +4d-4d

Combine like terms

-5cd

4 0

4 years ago

Which statement describes the sequence defined by

Llana [10]

Answer:

a) The given sequence is diverges

$\lim_{n \to \infty} a_n$ = ∞

Step-by-step explanation:

Explanation

Given that the $n^{th}$ term sequence

$a_{n} = \frac{n^{3} - n}{n^{2} + 5 n}$

we have to prove that a given sequence converges or diverges

$\lim_{n \to \infty}a_{n} = \lim_{n \to \infty} \frac{n^{3} - n}{n^{2} + 5 n}$

$= \lim_{n \to \infty} \frac{n^{3}(1- \frac{1}{n^{3} }) }{n^{2}(1+ \frac{5n}{n^{2} } )}$

$= \lim_{n \to \infty} \frac{n(1- \frac{1}{n^{3} }) }{(1+ \frac{5n}{n^{2} } )}$

= ∞

$\lim_{n \to \infty} a_n$ = ∞

The given sequence is diverges

7 0

4 years ago

Read 2 more answers

mr stephens needs to haul 1,518 tons of rocks from a construction site. His dump truck can hold 26 ton per load. how many tons w

lisov135 [29]

Answer:

Step-by-step explanation:

1518 divided by 26 is 58 remainder 10.

... 1518 = 26×58 + 10 = 1508 + 10

Mr. Stephens will make 58 trips with a full load. After that, 10 tons of rock will remain.

6 0

3 years ago

How do you calculate this

Alexxx [7]

Answer:

y = - 2x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 1, 1) and (x₂, y₂ ) = (0, - 1) ← 2 points on the line

m = $\frac{-1-1}{0-(-1)}$ = $\frac{-2}{0+1}$ = $\frac{-2}{1}$ = - 2

the line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y = - 2x - 1 ← equation of line

4 0

1 year ago