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2 years ago

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Mr. Valenzuela’s new bottle of shampoo contains 60 ounces of shampoo. He uses ounce of shampoo each time he washes his hair. Whi

ch equation can be used to find x, the number of washes after which 24 ounces will remain in the bottle?

2 answers:

nlexa [21]2 years ago

5 0

Answer:

$60-x=24$

Step-by-step explanation:

Total amount of shampoo = 60 ounces

Amount of shampoo used in 1 wash = 1 ounce

Amount of shampoo used in x washes = x ounces

So, Remaining amount of shampoo = 60-x

We are given that 24 ounces will remain in the bottle

So, equation becomes : $60-x=24$

Hence equation can be used to find x, the number of washes after which 24 ounces will remain in the bottle is $60-x=24$

Verizon [17]2 years ago

4 0

This is the correct answer.

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Anika [276]

Answer:

The perimeter of triangle is 19.8 units

Step-by-step explanation:

we know that

The perimeter of triangle ABC is

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

we have

$A(-2,3),B(3,0)$

substitute in the formula

$d=\sqrt{(0-3)^{2}+(3+2)^{2}}$

$d=\sqrt{(-3)^{2}+(5)^{2}}$

$d_A_B=\sqrt{34}\ units$

step 2

Find the distance BC

we have

$B(3,0),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(-4-3)^{2}}$

$d=\sqrt{(-3)^{2}+(-7)^{2}}$

$d_B_C=\sqrt{58}\ units$

step 3

Find the distance AC

we have

$A(-2,3),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-3)^{2}+(-4+2)^{2}}$

$d=\sqrt{(-6)^{2}+(-2)^{2}}$

$d_A_C=\sqrt{40}\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=\sqrt{34}+\sqrt{58}+\sqrt{40}$

$P=19.8\ units$

4 0

2 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago

Find the compunt intrest on rs 31250 at 12 % per annum for 12 1/2 years

postnew [5]

Answer:

<h2>$128847</h2>

Step-by-step explanation:

given Principle at 31250

and rate = 12%

and time 12.5 years

the amount would be given by the equation

$P(1+\frac{rate}{100})^{time}$

plug in values to get

$31250(1+\frac{12}{100})^{12.5}$

end up with value $128847

3 0

2 years ago

Which of the following expressions simplifies to a negative number? Select all that apply.

Contact [7]

Answer:

(-1)(-1)(-1)

(-1)(-1)(-1)(-1)(-1)

These, since they are all negatives and there are an odd number of terms.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

{(2,-4),(3,-4),(4,-4),(5,-4),(6,-4)}

Musya8 [376]

Answer:

I agree with Selena. Since the x's do not repeat, it is a function.

Step-by-step explanation:

3 0

2 years ago