Answer:
The cutoff sales level is 10.7436 millions of dollars
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
15th percentile:
X when Z has a pvalue of 0.15. So X when Z = -1.047.
The cutoff sales level is 10.7436 millions of dollars
Hello!
First, find angle BOA on the protractor. To do this, look for point B, point O, and point A.
Now, we see some markings that mark what degree point B and point A are at. Point B is marked at 60 degrees, and Point A 40 degrees.
Now, all that's left to do, is subtract the two measurements.
60 degrees - 40 degrees = 20 degrees
Therefore, your answer is 20.
Hope this helps!
Answer:
1 maps to 1
2 maps to 3
3 maps to 2
Step-by-step explanation:
the correctly assigned answer options describe everything.
there is not much else to say and explain.
these are all true statements due to the symmetry principle of a circle.
when 2 direct connections of two points on the circumference of a circle have the same length, then also their bent distances on the circumference of the circle are the same. and vice versa.
and yes, the perpendicular radius (or diameter) of the circle towards such a line cuts this line in half.
The GCF of the first two is 4p³q².The GCF of the second two is 8pq⁵.The GCF of the third two is 4p²q⁵.The GCF of the fourth two is 8p²q.The GCF of the fifth two is 4p²q.
To find the GCF of each pair, find the greatest number that will divide into each coefficient. As for the variable portions, choose the variable that has the smallest exponent from each pair.
