The true comparison is the typical value is greater in set A. The spread is greater in set B.
<h3>What is the true comparison?</h3>
Spread is used to measure the variability of a data set. Range can be used to measure spread. Range is the difference between the largest number and the smallest number in the dataset.
- Spread of set A = 7 - 5 = 2
- Spread of set B = 8 - 1 = 7
The median can be used to measure the typical value of the dataset. Median is the number at the center of the data set.
- Median of set A = 6
- Median of set B = 4
To learn more about median, please check: brainly.com/question/14746682
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Substitute 4 for y. Then -3x^2 + 16 = 52.
Solve for x. Subtract 16 from both sides, obtaining -3x^2 = 36.
Divide both sides by -3, obtaining x^2 = -12. This last result makes no sense, as no square of a real number could be negative. Probably this is where you're ":getting a negative answer."
If imaginary answers were allowed, then x = i*√12 = i*2√3 or x = -i*2√3.
x =
Answer:
Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two.
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
x ----> the area of the enlarged garden
y ----> the area of the original garden

we have that
If Tessa multiplies each dimension by 2, then the scale factor equals 2.

substitute

The area of the enlarged garden will be equal 4 times the area of the original garden
so
If Tessa wanted to have twice as much surface, she must multiply each dimension by a square root of 2.
therefore
Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two
If i’m not mistaken it should be 55 because if you find the area of the whole triangle and subtract the mini rectangle you should get the shape