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Ostrovityanka [42]
2 years ago
15

On a horizontal number line, positive numbers are

Mathematics
1 answer:
soldi70 [24.7K]2 years ago
4 0

Answer:

to the right

Step-by-step explanation:

hope this helps✨

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40% of the memberships sold by Gym A were gold memberships.
Aneli [31]

Answer:

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

Step-by-step explanation:

Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.  

Which statement must be true?

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.

c) Gym A sold more gold membership than Gym A did.

d) If Gym B sold 50 membership, 25 would be gold memberships.

Given: Gym A have sold 40% gold membership of total membership.

Gym B have sold 25% gold membership of total membership.

Lets take option A first to find if it is true statement.

As per option A, There are total number of membership is 80.

∵ Gym A has sold 40% gold membership.

∴ Gym A gold membership= 40\% \times 80

⇒ Gym A gold membership= \frac{40}{100} \times 80= 32 member.

∴ Gym A gold membership= 32.

Now, Gym B

∵ Gym B has sold 25% gold membership.

∴ Gym B gold membership= 25\% \times 80

⇒ Gym B gold membership= \frac{25}{100} \times 80=20 member.

∴ Gym B gold membership= 20.

Next finding difference gold membership for Gym A and Gym B

32-20= 12 \ membership

Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.

8 0
2 years ago
Does anybody know the answer's to, 2,3, and 4?
Jobisdone [24]
2, No solution
3, Infinite many solutions
4, (0,-3)
i hope i was able to help!! so sorry if i made a mistake
7 0
2 years ago
Segment KJ shown below is the hypotenuse of isosceles right triangle JLK.
irga5000 [103]
On a coordinate plane it is negetive 5
7 0
3 years ago
Read 2 more answers
Pls guys help me pls :c​
Vinil7 [7]

Answer: A. x\geq21\dfrac{2}{3} .

Step-by-step explanation:

The given inequation: 81-1\dfrac{1}{5}x\leq55

\Rightarrow\ 81-\dfrac{6}{5}x\leq55

Multiplying 5 on both the sides, we get

5(81-\dfrac{6}{5}x)\leq5\times55\\\\\Rightarrow\ 405-6x\leq275\\\\\Rightarrow\ 6x\geq405-275\\\\\Rightarrow\ 6x\geq130\\\\\Rightarrow\ x\geq\dfrac{130}{6}\\\\\Rightarrow\ x\geq\dfrac{65}{3}\\\\\Rightarrow\ x\geq21\dfrac{2}{3}

Hence, the inequality for x is x\geq21\dfrac{2}{3} .

So, the correct option is A. x\geq21\dfrac{2}{3} ..

8 0
3 years ago
Can someone please help me with this? I keep getting half of the answer and I'm doing everything right. ------------------------
serg [7]

9514 1404 393

Answer:

  a. x, x+2, x+4

  b. 10 ≤ 3x+6 ≤ 24

  c. 6 ft, 8 ft, or 10 ft

Step-by-step explanation:

<u>Given</u>:

  • The lengths of the sides of a certain triangle, in feet, are consecutive even integers.
  • The perimeter of this triangle is between 10 feet and 24 feet inclusive.

<u>Find</u>:

  a. Using one variable, write three expressions that represent the lengths of the three sides of the triangle.

  b. Write a compound inequality to model this problem.

  c. Solve the inequality. List all possible lengths for the longest side of the triangle.

<u>Solution</u>:

You have let x represent the shortest side. (Note that the question asks for the length of the longest side.)

a. The expressions for side lengths can be x, x+2, x+4 when x is the shortest side.

__

b. Here is the compound inequality

  10 ≤ x+(x+2)+(x+4) ≤ 24

__

c. Here is the solution

  10 ≤ 3x+6 ≤ 24 . . . . collect terms

  4 ≤ 3x ≤ 18 . . . . . . . subtract 6

  4/3 ≤ x ≤ 6 . . . . . . . . divide by 3

<em>Your working is correct, but incomplete</em>. The values of interest are the even integers x+4.

  5 1/3 ≤ x+4 ≤ 10

The longest side may be 6 ft, 8 ft, or 10 ft.

6 0
2 years ago
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