probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
360
Step-by-step explanation:
f varies directly as g
f = kg where k is the constant of variation
f varies inversely as h
f = kg/h
We know g = 198 when h = –11 and f = –6. Substituting in
-6 = k*198/(-11)
-6 =k*(-18)
Dividing each side by -18
-6/-18 = k*-18/-18
1/3 =k
Our equation is
f = 1/3 g/h
Letting f = 12 and h = 10
12 = 1/3 g/10
Multiply each side by 10
12*10 =1/3 g/10*10
120 = 1/3 g
Multiply each side by 3
120*3 =1/3 g *3
360 =g
Answer x = 24 + 3x
Step-by-step explanation:
Answer:
median is the middle value
mean is the average
mode is the one that occurs most
range is the highest number - lowest number
