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Sever21 [200]
3 years ago
13

Can i get some help with #5 and below thankyou

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

v8

Step-by-step explanation:

what the other guy said!

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4x - 3 = 2x + 7 what would the answer be??
TiliK225 [7]

Answer:

x = 5

Step-by-step explanation:

Step 1: Subtract 2x from both sides.

4x−3−2x=2x+7−2x

<u>2x−3=7</u>

Step 2: Add 3 to both sides.

2x−3+3=7+3

<u>2x=10 </u>

Step 3: Divide both sides by 2.

2x/2 = 10/2

x=5

5 0
3 years ago
A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume t
sladkih [1.3K]

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

a)

\frac{dy}{dt}\ \alpha\  y(1-y)

\frac{dy}{dt}=ky(1-y)

where k is the constant of proportionality, dy/dt =  rate at which the rumor spreads

b)

\frac{dy}{dt}=ky(1-y)\\\frac{dy}{y(1-y)}=kdt\\\int\limits {\frac{dy}{y(1-y)}} \, =\int\limit {kdt}\\\int\limits {\frac{dy}{y}} +\int\limits {\frac{dy}{1-y}}  =\int\limit {kdt}\\\\ln(y)-ln(1-y)=kt+c\\ln(\frac{y}{1-y}) =kt+c\\taking \ exponential \ of\ both \ sides\\\frac{y}{1-y} =e^{kt+c}\\\frac{y}{1-y} =e^{kt}e^c\\let\ A=e^c\\\frac{y}{1-y} =Ae^{kt}\\y=(1-y)Ae^{kt}\\y=\frac{Ae^{kt}}{1+Ae^{kt}} \\at \ t=0,y=10\%\\0.1=\frac{Ae^{k*0}}{1+Ae^{k*0}} \\0.1=\frac{A}{1+A} \\A=\frac{1}{9} \\

y=\frac{\frac{1}{9} e^{kt}}{1+\frac{1}{9} e^{kt}}\\y=\frac{1}{1+9e^{-kt}}

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

y=\frac{1}{1+9e^{-0.8959t}}\\0.75=\frac{1}{1+9e^{-0.8959t}}\\t=3.68\ days

5 0
2 years ago
All of the following are rational except<br> Sqrt 0.49<br> Sqrt 19<br> Sqrt 900<br> Sqrt 100
Anna71 [15]

Answer:

0.49

Step-by-step explanation:

for it to be rational there should not be no decimal nor pi .

3 0
3 years ago
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Please and thank you
algol [13]

Answer:

the last one

Step-by-step explanation:

6 0
3 years ago
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Brian, Chris, and Damien took a math test that had 20 questions. The number of questions Brian got right is 14 more than 1/4 the
Minchanka [31]
I believe the answer to your question is A!
7 0
3 years ago
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