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bagirrra123 [75]

3 years ago

8

How do I do this, I really need some help

1 answer:

meriva3 years ago

4 0

You solve for x and get x<-2 or x>= -1/2 and then graph

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The earth is on average 92,900,000 miles from the sun. In July, the distance is 94,400,000 miles, the farthest of any month. Wha

irinina [24]

Answer:

4.468275*(10)^(11)

Step-by-step explanation:

Difference is 94400000-9290000=85110000 miles. This distance in feet is 4.468275*(10)^(11)

4 0

2 years ago

Please help!! :(((((

wel

Answer:

20+4(t)=?

Step-by-step explanation:

try using the vid :P

4 0

3 years ago

The time that a randomly selected individual waits for an elevator in an office building has a uniform distribution over the int

rewona [7]

Answer:

The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

Mean = 0.5

Standard deviaiton = 0.289

Sample of 12

By the Central Limit Theorem

Mean = 0.5

Standard deviation $s = \frac{0.289}{\sqrt{12}} = 0.083$

The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.

4 0

3 years ago

Does a proportional relationship have a constant rate of change?

Ghella [55]

Yes the proportial relationship all increase by the same number so that would be your rate of change

3 0

3 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)

Read more about rhombus at:

brainly.com/question/20627264

#SPJ1

8 0

1 year ago