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Taya2010 [7]
3 years ago
7

Demonstrate at least two different ways how to solve the equation 5^(2x+1)=25

Mathematics
1 answer:
aniked [119]3 years ago
7 0
5^(2x+1)=25 = ln5^(2x+1)=ln25 = (2x+1)ln5=ln25 = 2x+1=ln25-ln5 = 2x=ln5-1 = x=1/2*ln5-1 is exact form or approx.=-0.195

hope this helps! if you want another way to solve besides using logs then just let me know. Thanks!
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lakkis [162]

Answer:

Okay So I see you need to change 1/3 to a denominator of 6

You don't do anything to the -1/6

But to change the 1/3 you need to multiply 3 and 1 by two, which is 2/6

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5 0
3 years ago
What is x?????????????
Mekhanik [1.2K]

Answer:

BGC=180-90

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8 0
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7 0
3 years ago
Five dogs were running in a race. Bandit completed the race 10 seconds after Sergeant and 30 seconds before Sally. Smokey comple
ipn [44]

Answer:

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Step-by-step explanation:

7 0
4 years ago
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Makovka662 [10]
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or
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The solution of the first pair of equations is
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The solution of the first and last equations is
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The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.
8 0
3 years ago
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