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Mariulka [41]
3 years ago
8

Ratchpad Which line of reflection maps point Q at (1, 2) to point Q at (-2,-1)?

Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
Idk...................................
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HELP!! Can someone help me with this
cricket20 [7]

Answer:

1 no

2yes

3 no

4 no

5 Yes

6 Yes.

so it gives you a pattern right there a squared plus b squared equals c squared just fill in the numbers in that way

6 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81 - (x-6) ^2/89= 1?
GarryVolchara [31]

Answer:

I think its (6,-3)

Step-by-step explanation:

8 0
3 years ago
A bottle contains 24.5 oz of water. A leak in the bottle causes it to lose 0.3 oz of water every minute. How many minutes does i
Bogdan [553]

Answer:

There is 1.5 water left in the bottle

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Will give Brainliest! if right!
maksim [4K]
The answer is B 36 because the chance of you grabbing a white or black is 12/15 meaning if you pulled 15 marbles, most likely 12 of them are white or black. so, because 15 goes into 45 3 times, you multiply 12/15 by 3 getting 36/ 45 meaning you will mostly pull 26 black or white marbles.
6 0
3 years ago
A lay came to the market to sell eggs . We first customer bought 1/2 of all her eggs and 1/2 of an egg. Her second customer boug
Bezzdna [24]

Given:

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.

At this point she had sold all her eggs.

To find:

The number of egg the lady have when she came to the market.

Solution:

Let x be the number of egg that the lady have when she came to the market.

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

x-\dfrac{1}{2}x-\dfrac{1}{2}=\dfrac{x}{2}-\dfrac{1}{2}

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.  So, the number of remining egg after second customer is

\text{Remaining eggs}=\dfrac{x}{2}-\dfrac{1}{2}-(\dfrac{x}{2}-\dfrac{1}{2})\times \dfrac{1}{2}-\dfrac{1}{2}

=\dfrac{x}{2}-\dfrac{1}{2}-\dfrac{x}{4}+\dfrac{1}{4}-\dfrac{1}{2}

=(\dfrac{x}{2}-\dfrac{x}{4})+(-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{2})

=(\dfrac{2x-x}{4})+(\dfrac{-2+1-2}{4})

=\dfrac{x}{4}-\dfrac{3}{4}

At this point she had sold all her eggs. It means the remining eggs is 0.

\dfrac{x}{4}-\dfrac{3}{4}=0

\dfrac{x}{4}=\dfrac{3}{4}

Multiply both sides by 4.

x=3

Therefore, the lady came to the market is with 3 eggs.

8 0
3 years ago
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