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rosijanka [135]
3 years ago
11

What is 37 percent of 4214.12. And how do I do it.

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

p\%=\dfrac{p}{100}\\\\37\%=\dfrac{37}{100}=0.37\\\\37\%\ of\ 4214.12\ is\ 0.37\cdot4214.12=1559.2244

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You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw
VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend,  total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)

from (i), x=84-4y-2z    (*)

put this in (ii) and (iii) we get

2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)

from (iv), y=-\frac{z-92}{7}\ (vi)

\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)

-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8

\mathrm{Subsititute\:}z=8\text{ in (vi)}

y=-\frac{8-92}{7}\\\\\Rightarrow \ y=12

\mathrm{Subsititute\:}z=8,\:y=12\text{ in (*)}

x=84-4\cdot \:12-2\cdot \:8\\\\\Rightarrow\ x= 20

Hence, x= 20, y= 12 , z=8

So, Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

7 0
3 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
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