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3 years ago

Need help ASAP m<2=92 m<12=74

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

nevermind, i figured it out!

<10 = 92

<8 = 92

<9 = 88

<5 = 106

<11 = 106

<13 = 106

yes these are actually the answers, lol

Step-by-step explanation:

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Solve the system of linear equations below. 2x + 3y = 2 x + 6y = 4 x........A.X=0, y =2/3..B..x =2, y = -2/3...C..x=4/3, y=2/9..

Bogdan [553]

I will solve your system by substitution.2x+3y=2;x+6y=4xStep: Solve2x+3y=2for x:2x+3y+−3y=2+−3y(Add -3y to both sides)2x=−3y+22x2=−3y+22(Divide both sides by 2)x=−32y+1Step: Substitute−32y+1forxinx+6y=4x:x+6y=4x−32y+1+6y=4(−32y+1)92y+1=−6y+4(Simplify both sides of the equation)92y+1+6y=−6y+4+6y(Add 6y to both sides)212y+1=4212y+1+−1=4+−1(Add -1 to both sides)212y=3212y212=3212(Divide both sides by 21/2)y=27Step: Substitute27foryinx=−32y+1:x=−32y+1x=−32(27)+1x=47(Simplify both sides of the equation)Answer:x=4/7 and y=2/7
is what i got sorry if it don't help

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4 years ago

Whats is the prouduct for 4/5 3/7

Makovka662 [10]

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▹ Answer

12/35

▹ Step-by-Step Explanation

$\frac{4}{5} * \frac{3}{7} \\\\= \frac{12}{35}$

Hope this helps!

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5 0

3 years ago

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The probability distribution for the random variable x follows. x f(x) 20 0.20 25 0.15 30 0.30 35 0.35 (a) Is this probability d

Damm [24]

Answer:

(a) The probability distribution is valid.

(b) The probability that x = 30 is 0.30.

Step-by-step explanation:

The probability distribution of the random variable X is:

x: 20 | 25 | 30 | 35

f (x): 0.20 | 0.15 | 0.30 | 0.35

(a)

The properties of a probability distribution are:

0 ≤ P (X) ≤ 1
∑ P (X) = 1

All the probability value are more than 0 and less than 1.

Compute the sum of all the probabilities as follows:

$\sum P(X)=0.20+0.15+0.30+0.35=1$

The sum of all probabilities is 1.

Thus, the probability distribution is valid.

(b)

Consider the probability distribution table.

The probability of X = 30 is,

P (X = 30) = 0.30.

Thus, the probability that x = 30 is 0.30.

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4 years ago

Can atriangle be formed with side lengths of 5cm. 10cm and 15cm

andreyandreev [35.5K]

Theorem of cosine:
a²=b²+c²-2bc(cos α) ⇒cos α=-(a²-b²-c²) / 2bc

In this case:
a=15 cm
b=10 cm
c=5 cm

cos α=-(15²-10²-5²) / 2*10*5
cos α=-100 / 100
cos α=-1

A=arc cos -1=180º This is impossible, because:

A+B+C=180º; then B=C=0º This is impossible for make a triangle (B>0 and C>0 if we want to make a triangle).

Therefore: it is not possible can make a triangle with side lengths of 5 cm, 10 cm and 15 cm.

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4 years ago

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jeyben [28]

Answer:

Step-by-step explanation:

the solution is x+2y - 3z =15. 2x – 2z=6 x = 3. 2/3)-22=6.

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3 years ago

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