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gulaghasi [49]
1 year ago
14

suppose+a+study+claims+that+the+results+are+significant+at+the+1%+significance+level.+which+of+the+following+does+this+not+imply

?
Mathematics
1 answer:
Alenkinab [10]1 year ago
3 0

The observed results would be very unlikely if the alternative hypothesis were true.

What does the alternative hypothesis mean?

A statement used in experiments using statistical inference is known as the alternative hypothesis. It is indicated by Ha or H1 and runs counter to the null hypothesis.

                 Alternatively, it is only a null-free option, as we can also state. An alternative theory is a claim that a researcher is testing in a hypothesis test.

What is an illustration of a different hypothesis?

Just like the null, the alternative hypothesis is an option. For instance, if your null is "I'm going to win up to $1,000" and your alternate is "I'm going to win $1,000 or more," you're essentially determining whether there is sufficient variance in the alternate hypothesis to allow you to reject the null hypothesis.

Learn more about alternative hypothesis

brainly.com/question/27335001

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Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ<2π0≤θ<2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

6 0
3 years ago
I’m 11 years old <br><br><br><br><br><br><br><br><br><br>Jk I’m not I could rlly use a hand tho
horsena [70]

Answer:

880

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Some people took part in a game. The frequency shows information about their scores.
Marizza181 [45]

Answer:

The mean = 17.54

Step-by-step explanation:

Form a table as below;

<u>Interval         Frequency{f}      Midpoint of frequency{x}          fx    </u>

1-7                    19                         4                                            76

8-10                  14                         9                                            126

11-15                  15                         13                                           195

16-20                20                        18                                           360

21-35                 10                        28                                          280

36-50                13                         43                                          559

Sum                   91                                                                        1596

The mean  of grouped data = Sum of { Interval Midpoint * Frequency } /Sum of frequency

The mean= 1596 / 91

The mean = 17.54

5 0
3 years ago
Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random
Katen [24]

Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

x_2 = 54 --- City K

Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

7 0
3 years ago
The ball used in a soccer game may not weigh more than 16 ounces or less
Liono4ka [1.6K]
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
3 0
3 years ago
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