Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME
1 answer:
Answer:
58°
Step-by-step explanation:
If m AM=125°, then m∠AOM=125°.
If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).
Thus,
m∠FOA=360°-150°-125°=85°.
If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).
Hence,
m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.
Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus
m∠AME=1/2m∠EOA=58°.
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