-y+10+3y=14+y-2 solve for y
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Answer:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
Step-by-step explanation:
We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that and
, then the translation vector is:
It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).
