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Ahat [919]
3 years ago
8

I domt understand slope at all

Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0

slope = 2 and y-intercept = 0

the equation of a line in ' slope- intercept form ' is

y = mx + c  ( mis the slope and c the y-intercept )

given 2x - y = 0 ( add y to both sides )

2x = y or y = 2x + 0 ← in slope-intercept form

with slope m = 2 and y-intercept c = 0


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LUCKY_DIMON [66]

Using derivatives, the rate of change of the mineral level with respect to time for 4 days is -0.012 mg/cm².

<h3>What is the missing information?</h3>

The function for the amount is missing, and is given by:

C(t) = \frac{1}{2}(6t + 1)^{-\frac{1}{2}}

The problems asks for the rate of change of the mineral level with respect to time for 4 days.

<h3>What is the rate of change after 4 days?</h3>

The rate of change after 4 days is given by:

C'(4).

Applying the chain rule, the derivative of C(t) is given as follows:

C^{\prime}(t) = \frac{1}{2}(6t+1)^\prime \times -\frac{1}{2} \times (6t+1)^{-\frac{3}{2}}

C^{\prime}(t) = -\frac{3}{2}(6t+1)^{-\frac{3}{2}}

When t = 4, we have that:

C^{\prime}(4) = -\frac{3}{2}(6(4)+1)^{-\frac{3}{2}}

C^{\prime}(4) = -\frac{3}{2}(25)^{-\frac{3}{2}}

Applying properties of exponents, we have that:

(25)^{-\frac{3}{2}} = \left(\frac{1}{25}\right)^{\frac{3}{2}} = \frac{1}{\sqrt{25^3}} = \frac{1}{25\sqrt{25}} = \frac{1}{125}

Hence:

C^{\prime}(4) = -\frac{3}{2} \times \frac{1}{125}

C'(4) = -0.012.

The rate of change of the mineral level with respect to time for 4 days is -0.012 mg/cm².

More can be learned about derivatives at brainly.com/question/23819325

#SPJ1

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1 year ago
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From this, you can simplify by dividing by -2

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