The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:

Expand the function

Reorder the terms

Factor the expression

Factor out x -1

Expand

Factorize
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Factor out x + 2

The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer:
Slope is 9.
Step-by-step explanation: The formula to find slope is m= y2-y1/x2-x1
-6=y1, -4=x1/ 3=y2, -4=x2
3-(-6)/-4-(-4)
=9/0=9
The Slope is 9.
I hope that this has helped, have a good day.
Answer:
12
Step-by-step explanation:
quarterly means 4
3*4 = 12
Answer:
if the - after simplify is involved it would be 10, 9 and if it's not it's -9, -10.
Answer:
x= 12 and Angle Q measures 60 degrees
Step-by-step explanation:
Supplementary angles are two angles added together to make 180.
So 5x +120= 180 subtract 120 from both sides
5x=60 divide both sides by 5
x= 12
Angle Q= 5 times 12 = 60