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3 years ago

A store pays a 6% commission on the first $500 in sales and and 8% on sales over $500. Find the commission on an $800 sale

1 answer:

5 0

First you need to understand the structure of the commission.
The first part is 6% commission on sales up to $500.
The second part is 8% commission on sales over $500.

Note that the second part doesn't mean that a sale of $800 gets 8% of $800.

It means that once we have reached $500, any *further* sales get 8%.
Since $800 is $300 more than $500, the commission is

6% of $500 +
8% of $300

The first thing she did was work out the excess above $500.
Then she worked out the two percentages in two separate parts.

The second part seems to have incurred a cut and past accident, not sure if that is yours or it was already done.

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A typical tip in a restaurant is 15% of the total bill. If the bill is $90, what would the typical tip be?

Lana71 [14]

Answer:

$13.50 typical tip

Step-by-step explanation:

So to find the percentage

multiply 0.15*90

You’ll get 13.5

6 0

3 years ago

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An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre

melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let $\mu$ = mean power consumption for microwave ovens.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 250 W {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, $H_A$ : $\mu$ > 250 W {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean power consumption for ovens = 257.3 W

σ = population standard deviation = 15 W

n = sample of microwave ovens = 20

So, the test statistics = $\frac{257.3-250}{\frac{15}{\sqrt{20} } }$

= 2.176

The value of z test statistics is 2.176.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

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3 years ago

Which statements about the values of 4.099 and 40.99 are true? Select all that apply. 4.099 is 110 of 40.99. 4.099 is 1100 of 40

liraira [26]

Answer:

40.99 is 10 times more than 4.099

Step-by-step explanation:

Given the values :

4.099 and 40.99

4.099 is 110 of 40.99 : 110 * 40.99 = 4508.9 (false)

4.099 is 1100 of 40.99 : 1100 * 40.99 = 45089 (false)

40.99 is 10 times more than 4.099 : (10 * 4.099) = 40.99 (true)

40.99 is 100 times more than 4.099 : (100 * 4.099) = 409.9 ( false)

4.099 is 10 times more than 40.99 : (10 * 40.99) = 409.9 (false)

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3 years ago

What's the answer anyone know?

Katyanochek1 [597]

The answer is -2/6
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4 years ago

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Vlad1618 [11]

Answer:

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Step-by-step explanation:

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3 years ago

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