It's maybe right. I'm not sure
2x+3x+5+8+8c+4c+7+6+5+0+9
2 answers:
You might be interested in
YOU CAN EVEN WRITE IT IN THE FRACTION FORM .
BE REMINDED THAT <> CHANGE SIGN WHEN YOU DIVIDE OR MULTIPLY A NEGATIVE NUMBER ONLY.
HOPE THIS HELPS
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Step-by-step explanation:
Given ,
Current balance $320
Minimum balance $100
I could spent =$(320-100) = $220
Let the number of bills be x.
Total amount of x bills = $20x
According to the problem,
20x≤ 220
⇔x ≤
⇔x≤11
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.