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4 years ago

20 POINTS TO BRAINLIEST!!! PLEASE HELPP!!!!

Mathematics

2 answers:

Agata [3.3K]4 years ago

8 0

Answer:

$\huge\boxed{15 \° C}$

Step-by-step explanation:

$C = \frac{5}{9} ( F - 32)$

Where F = 59 °F

$\sf C = \frac{5}{9} (59-32)\\C = \frac{5}{9} ( 27)\\C = 5 * 3\\C = 15 \ degrees \ Celsius$

Yuki888 [10]4 years ago

4 0

Answer:

Step-by-step explanation:

So we want to convert 59°F to Celsius using the given formula:

$C=\frac{5}{9}(F-32)$

Thus, substitute F for 59:

$C=\frac{5}{9}(59-32)$

Subtract:

$C=\frac{5}{9}(27)\\$

Simplify:

$C=\frac{135}{9}=15\textdegree F$

The answer is A

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zlopas [31]

The answer is 7/10.

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Solve the equation by factoring. z2 − 6z − 27 = 0

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Answer:

The answer is x= 9 and -3

You must fine 2 number that multiply to equal -27 and add to equal -6

(x-9) (x+3)

Then equal the parts of the binomial to zero

x - 9 = 0

x + 3 = 0

You must get x by its self.

When you do so, you'll have the answer as -3 and 9

Step-by-step explanation:

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3 years ago

Which of the following graphs shows the solution to the system of equations y=5x-1 and y= x+3

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Where are the graphs?

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3 years ago

Simplify the surd 3√ 20 +√ 45

melisa1 [442]

Answer:

9 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the radicals

$\sqrt{20}$

= $\sqrt{4(5)}$

= $\sqrt{4}$ × $\sqrt{5}$

= 2 $\sqrt{5}$

$\sqrt{45}$

= $\sqrt{9(5)}$

= $\sqrt{9}$ × $\sqrt{5}$

= 3 $\sqrt{5}$

Then

3 $\sqrt{20}$ + $\sqrt{45}$

= 3(2 $\sqrt{5}$ ) + 3 $\sqrt{5}$

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3 years ago

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The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

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4 years ago