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MatroZZZ [7]
3 years ago
6

2. Alex drew a scale drawing of an auditorium. He used the scale 3 inches = 2 feet. If the stage is 30 inches in the drawing, ho

w wide is the actual stage? Enter your answer with units.
3. Mei is on a biking tour of Europe. While looking at a map of the tour route, she notices that the next two stops are 9 centimeters apart. What is the actual distance between the next two stops if the scale of the map is 3 centimeters = 8 kilometers? Enter your answer with units.

4. Bella is river rafting in Lewis County. The starting and ending points of the trip are 4 inches apart on a map of the river. In real life, these two points are 36 miles away from each other. What is the scale of the map?
1 inch : _____ miles

5. Brett made a scale drawing of an Italian restaurant. The restaurant's kitchen is 3 centimeters long in the drawing. The actual kitchen is 21 meters long. What scale did Brett use for the drawing?
1 centimeter : ____ meters
Mathematics
1 answer:
maksim [4K]3 years ago
6 0

2. The scale is 3 inches = 2 feet.

Divide total inches by 3, then multiply by 2:

30 / 3 = 10

10*2 = 20 feet.

3. Divide the 9cm by 3cm, then multiply by 8 km

9/3 = 3

3*8 = 24 kilometers.

4. Divide real distance by distance on map:

36 / 4 = 9

1 inch = 9 miles

5. Divide real dimension by the drawing dimension:

21 meters / 3 centimeters = 7

1 cm = 7 meters

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Let P be a point not on line k Let p be the image of P after a reflection about the line K and let A any point on line k. Determ
Alexus [3.1K]

Answer: true false some true

Step-by-step explanation:

5 0
2 years ago
Find the length of GI in the triangle below. Show your work.
love history [14]

Answer:

<u>The length of GI is 90.06 units</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

GH = 60 units

HI = 42 units

∠H = 123°

2. Using the Law of Cosines, we can find the length of GI, this way:

GI² = GH² + HI² - 2 * GH * HI * cos ∠H

Replacing with the real values:

GI² = 60² + 42² - 2 * 60 * 42 * cos ∠123°

GI² = 3,600 + 1,764 - 2 * 60 * 42 * -0.545

GI² = 3,600 + 1,764 - 2 * 60 * 42 * -0.545

GI² = 3,600 + 1,764 + 2,746.8

GI² = 8,110.8

<u>GI = √ 8,110.8 = 90.06 units</u>

4 0
3 years ago
Read 2 more answers
Petrina had a piece of red ribbon that measured 2.4 m long. she also had a piece of blue ribbon which was 7 8 m long. what was t
katen-ka-za [31]

The total length of red and blue ribbons is 10.2 m.

Given that, the length of the red ribbon =2.4 m and the length of the blue ribbon =7.8 m.

<h3>How to add two decimals?</h3>

Adding decimals is similar to the usual addition of whole numbers. We know that a decimal number is a number with a whole number part and a fractional part which is separated by a decimal point.

Now, the length of the red ribbon + the length of the blue ribbon=2.4+7.8

=10.2 m

Therefore, the total length of red and blue ribbons is 10.2 m.

To learn more about the addition of decimals visit:

brainly.com/question/17612968.

#SPJ4

7 0
2 years ago
Of the relations graphed below, three are functions and one is not.
AlekseyPX

Answer:

Graph B

Step-by-step explanation:

the line is at some point perpendicular to the y-axis, there is no unique y value for this x value, which contradicts the definition of a function.

7 0
2 years ago
What is the perimeter of △ABC?
timofeeve [1]
<h3>Given</h3>
  • ΔABC
  • A(-3, -1), B(0, 3), C(1, 2)
<h3>Find</h3>
  • the length of the perimeter of ΔABC to the nearest tenth
<h3>Solution</h3>

The perimeter of a triangle is the sum of the lengths of its sides. The length of each side can be found using the Pythagorean theorem. Effectively, each pair of points is treated as the end-points of the hypotenuse of a right triangle with legs parallel to the x- and y-axes. The leg lengths are the differences betweeen the x- and y- coordinates of the points.

The difference of the x-coordinates of segment AB are 0-(-3) = 3. The y-coordinate difference is 3-(-1) = 4. So, the leg lengths of the right triangle whose hypotenuse is segment AB are 3 and 4. The Pythagorean theorem tells us

... AB² = 3² +4² = 9 +16 = 25

... AB = √25 = 5

You may recognize this as the 3-4-5 triangle often introduced as one of the first ones you play with when you learn the Pythagorean theorem.

LIkewise, segment AC has coordinate differences of ...

... C - A = (1, 2) -(-3, -1) = (4, 3)

These are the same leg lengths (in the other order) as for segment AB, so its length is also 5.

Segment BC has coordinate differences ...

... C - B = (1, 2) -(0, 3) = (1, -1)

The length of the line segment is figured as the root of the sum of squares, even though one of the coordinate differences is negative. The leg lengths of the right triangle used for finding the length of BC are the absolute value of these differences, or 1 and 1. Then the length BC is

... BC = √(1² +1²) = √2 ≈ 1.4

So the perimeter of the triangle ABC is

... AB + BC + AC = 5 + 1.4 + 5 = 11.4 . . . . perimeter of ∆ABC in units

_____

Please be aware that the advice to "round each step" is <em>bad advice,</em> in general. For real-world math problems, you only round the final result. You always carry at least enough precision in the numbers to ensure that there will not be any error in the final rounding.

In this problem, the only number that is not an integer is √2, so it doesn't really matter.

7 0
3 years ago
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