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Vsevolod [243]
2 years ago
13

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

The time required for one wing beat is 5 milliseconds.

<em><u>Explanation</u></em>

Lets assume, the time required for one wing beat is  t seconds

So, the time required for 200 wing beat = 200t seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds

So, the time required for one wing beat is 5 milliseconds.

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Hey there!

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You can find them by asking if each number can go into 6.

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The requirements we have is that they must be consecutive <u>and</u> have a product of 6.

Consecutive means right after one another.

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Hope this helps!

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