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Vsevolod [243]
3 years ago
13

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

The time required for one wing beat is 5 milliseconds.

<em><u>Explanation</u></em>

Lets assume, the time required for one wing beat is  t seconds

So, the time required for 200 wing beat = 200t seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds

So, the time required for one wing beat is 5 milliseconds.

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The equations given are in standard form. Put each equation in slope-intercept form. State the slope and the
rusak2 [61]

Answer:

3. \displaystyle y = \frac{2}{5}x + 1\frac{2}{5}

2. \displaystyle y = -\frac{5}{7}x + 2

1. \displaystyle y = -2x + 4

Step-by-step explanation:

3. 2x - 5y = −7

- 2x - 2x

__________

\displaystyle \frac{-5y}{-5} = \frac{-2x - 7}{-5} \\ \\ y = \frac{2}{5}x + 1\frac{2}{5}

2. 5x + 7y = 14

- 5x - 5x

__________

\displaystyle \frac{7y}{7} = \frac{-5x + 14}{7} \\ \\ y = -\frac{5}{7}x + 2

1. 6x + 3y = 12

- 6x - 6x

__________

\displaystyle \frac{3y}{3} = \frac{-6x + 12}{3} \\ \\ y = -2x + 4

I am joyous to assist you anytime.

8 0
3 years ago
I have attached the question IF ANSWERED WITHIN 10 MINUTES I WILL AWARD BRAINLIEST
Reil [10]
<3 +<4= 180
<3+25+52=180 from here <3=180-77=103
using this in first equation: 103+<4=180  <4=180-103=77
as you can see <4=77 which is the the sum of 25+52
8 0
3 years ago
A spinner used in a board game is divided into 12 equally sized sectors. Seven of these sectors indicate that the player should
xeze [42]

Answer:

20.8 inches squared

Step-by-step explanation:

Area of spinner:

45.1 is the area of sectors where the token doesn't move, which 5 sectors doesn't move the token (don't forget that the bonus points doesn't move token). Then

45.1/5=9.02

9.02*12=108.24

K=1/2(r^2)sin150

108.24=1/2(r^2)sin150

216.48=(r^2)1/2

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7 0
3 years ago
What is the length of line segment PQ? If you can please explain, thanks.
nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

\Rightarrow 4\times (x+4) = 6^2

\Rightarrow 4x+16 = 36

Subtract 16 from both sides.

\Rightarrow 4x+16-16 = 36-16

\Rightarrow 4x =20

Divide by 4 on both sides.

$\Rightarrow\frac{4x}{4}=\frac{20}{4}

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The length of line segment PQ is 5 units.

5 0
3 years ago
Read 2 more answers
3) Solve the System of Equations using Elimination/Combinations. (5 points)
Schach [20]

Answer:

(1, 2 )

Step-by-step explanation:

Given the 2 equations

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Multiplying (2) by 2 and adding result to (1) will eliminate x- term

2x + 4y = 10 → (3)

Add (1) and (3) term by term to eliminate x

0 + 3y = 6

3y = 6 ( divide both sides by 3 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for x

Substituting into (2)

x + 2(2) = 5

x + 4 = 5 ( subtract 4 from both sides )

x = 1

solution is (1, 2 )

3 0
3 years ago
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