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3 years ago

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Mathematics

1 answer:

Fiesta28 [93]3 years ago

7 0

The time required for one wing beat is 5 milliseconds.

Explanation

Lets assume, the time required for one wing beat is $t$ seconds

So, the time required for 200 wing beat $= 200t$ seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

$200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds$

So, the time required for one wing beat is 5 milliseconds.

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