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Vsevolod [243]
3 years ago
13

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

The time required for one wing beat is 5 milliseconds.

<em><u>Explanation</u></em>

Lets assume, the time required for one wing beat is  t seconds

So, the time required for 200 wing beat = 200t seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds

So, the time required for one wing beat is 5 milliseconds.

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P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

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P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

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So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

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2 years ago
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3 years ago
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