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Anuta_ua [19.1K]
3 years ago
13

Give the domain and range of each relationship. Determine whether or not each relationship is a function.

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

47

Step-by-step explanation:

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Which represents a total cost of 2 dance tickets at a price of c for each, less a one-time $5 discount?
Eduardwww [97]

The statement is represented as 2(c- 5). Option D

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions consisting of variables, terms, factors, and constants.

They are also made up of mathematical operations such as addition, bracket, subtraction, division, multiplication, etc

From the information given, we have;

  • total cost of 2 dance tickets
  • price of c for each, less a one-time $5 discount

Expressed as;

2(c- 5)

Thus, the statement is represented as 2(c- 5). Option D

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brainly.com/question/4344214

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HELP consider the table of values shown . The relationship of x to y is represented by which equation ?
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Whatever the x value is you have to add 9 to it.
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3 years ago
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
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