(2x-8)(7x+5)=0
2x-8=0
Divide both sides by 2
X-4=0
Add 4 to both sides
X=4
7x+5=0
Subtract 5 from both sides
7x=-5
Divide both sides by 7
X=-5/7
X=4, x=-5/7
Hope this helps :)
Answer:
Dimensions of cabinet
x (wide) = 1.93 ft
y (hight) = 2.895 ft
p (depth) =0.43 ft
Step-by-step explanation:
Dimensions of cabinet
y height
x wide
p deph
From problem statement
y = 1.5 x V = y * x * p V = 1.5*x²p but p = V/y*x p = 2.4/1.5 x²
p = 1.6 / x²
Then
Area of top and bottom A₁ = 2*x*p ⇒ 2*x*1.6/x²
A₁ = 3.2 /x
And cost in $ C₁ = 0,9 * 3.2 /x ⇒ C₁ = 2.88/x
Area of sides (front and rear not included)
A₂ = 2*y *p A₂ = 3*x*1.6/x² A₂ = 4.8/x
And cost in $ C₂ = 0.9 * 4.8 /x C₂ = 4.32 /x
Area of front and rear A₃ =2* y*x A₃ = 2*1.5 *x² A₃ = 3x²
And cost C₃ = 0.3 * 3/x² = 0.9/x²
Total cost C(x) = C₁ + C₂ + C₃ C(x) = 2.88/x + 4.32/x + 0.9x²
Taking derivatives
C´(x) = -2.88/x² - 4.32 /x² + 0.9 x
C´(x) = 0 -2.88/x² - 4.32/x² + 0.9 x = 0 -2.88 - 4.32 + 0.9 x³ = 0
-7.2 + x³ = 0 x³ = 7.2
x = 1.93 ft y = 1.5*1.93 = 2.895 ft and p = 0.43 ft
Answer:
Step-by-step explanation:
The set of values of x for which y will be a real number according to Y=8/x-3 includes all real numbers except x = 3.
<em>Real numbers in mathematics include the positive and negative integers and fractions (or rational numbers) and also the irrational numbers.</em>
- In essence, the expression Y=8/x-3 only ceases to yield a real number value for y if the denominator becomes zero.
When the denominator becomes zero, the value of y becomes undefined and thus is not a real number.
Therefore, if we set;
Consequently, the set of values of x for which y will be a real number according to Y=8/x-3 includes all real numbers except x = 3.
Read more:
brainly.com/question/7672375
Answer:
yes.
Step-by-step explanation: