Answer:
G(6,2)
Step-by-step explanation:
If point
is the midpoint of the segment GJ, where
and
, then
![x_F=\dfrac{x_G+x_J}{2},\\ \\y_F=\dfrac{y_G+y_J}{2}.](https://tex.z-dn.net/?f=x_F%3D%5Cdfrac%7Bx_G%2Bx_J%7D%7B2%7D%2C%5C%5C%20%5C%5Cy_F%3D%5Cdfrac%7By_G%2By_J%7D%7B2%7D.)
In your case,
therefore,
![2=\dfrac{x_G+(-2)}{2},\\ \\5=\dfrac{y_G+8}{2}.](https://tex.z-dn.net/?f=2%3D%5Cdfrac%7Bx_G%2B%28-2%29%7D%7B2%7D%2C%5C%5C%20%5C%5C5%3D%5Cdfrac%7By_G%2B8%7D%7B2%7D.)
Thus,
![x_G-2=4\Rightarrow x_G=6,\\ \\y_G+8=10\Rightarrow y_G=2.](https://tex.z-dn.net/?f=x_G-2%3D4%5CRightarrow%20x_G%3D6%2C%5C%5C%20%5C%5Cy_G%2B8%3D10%5CRightarrow%20y_G%3D2.)
It would be 40% is an apple at first, the peach would be 66%.
An equivalent fraction? So.. the fraction has to be equivalent to 3/5, correct?
One question, what do you mean by "tenth-size strip"?
Sorry but this question isn't clear enough.
Sorry :/
Answer:
![x_0=-5\\x_1=-2\\x_2=1\\x_3=4\\x_4=7](https://tex.z-dn.net/?f=x_0%3D-5%5C%5Cx_1%3D-2%5C%5Cx_2%3D1%5C%5Cx_3%3D4%5C%5Cx_4%3D7)
Δn=3
Step-by-step explanation:
Remember, if we need to divide the interval (a,b) in n equal subinterval, then we need divide the distance (d) between the endpoints of the interval and divide it by n. Then the width Δn of each subinterval is d/n.
We have the interval [-5,7]. The distance between the endpoints of the interval is
.
Now, we divide d by 4 and obtain ![\frac{d}{4}=\frac{12}{4}=3](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B4%7D%3D%5Cfrac%7B12%7D%7B4%7D%3D3)
Then, Δn=3.
Now, to find the endpoints of each sub-interval, we add 3 from the left end of the interval.
![-5=x_0\\x_0+3=-5+3=-2=x_1\\x_1+3=1=x_2\\x_2+3=4=x_3\\x_3+3=7=x_4](https://tex.z-dn.net/?f=-5%3Dx_0%5C%5Cx_0%2B3%3D-5%2B3%3D-2%3Dx_1%5C%5Cx_1%2B3%3D1%3Dx_2%5C%5Cx_2%2B3%3D4%3Dx_3%5C%5Cx_3%2B3%3D7%3Dx_4)
So,
![x_0=-5\\x_1=-2\\x_2=1\\x_3=4\\x_4=7](https://tex.z-dn.net/?f=x_0%3D-5%5C%5Cx_1%3D-2%5C%5Cx_2%3D1%5C%5Cx_3%3D4%5C%5Cx_4%3D7)