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Svetradugi [14.3K]
3 years ago
12

When o-bromoanisole is treated with nanh2 in nh3 (l), a reaction proceeding via a benzyne intermediate, what two isomeric produc

ts are possible? (check two products)?

Chemistry
1 answer:
Dominik [7]3 years ago
6 0

When orthobromoanisole is treated with sodamide (NaNH₂) and ammonia (NH₃), benzyne is formed and the tripple bond is formed between C₂-C₃ carbon atoms of benzene ring. Then NH₂⁻  can attack at ortho position as well as meta position.

The reaction takes place in three steps. Step-1:The amide NH₂⁻ ion attacks the  H -atom that is ortho to  C3 , generating a carbanion. Step-2:Loss of  Br -  to form a benzyne intermediate.Step-3:Addition of  NH₂⁻ ion. The strain caused by a triple bond in a benzene ring can be relieved by a nucleophilic addition  of NH₂⁻.

Two isomeric products are formed:  (1) <em>o</em>-methoxyaniline and (2) <em>m</em>-methoxyaniline. The structures of both the isomeric products are given in diagram.

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How many moles are in 15.2 grams of Calcium (Ca)?
nalin [4]

Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

  • grams to moles
  • moles to grams
  • grams to particles
  • moles to liters

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

  • <u>Mole</u> - a unit of measurement in chemistry

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

<u>Now, how do we find the number of moles?</u>

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

<u>How do we work this out?</u>

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

  • \text{15.2 grams Ca}

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

  • \displaystyle \frac{\text{40.08 grams Ca}}{\text{1 mole Ca}}
  • \displaystyle \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}

Now, we need to simplify a little bit.

\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}

<u>Are we done yet?</u>

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

  • 15.2 -- Three significant figures
  • 40.08 -- Four significant figures

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

0.379241517 \approx 0.379

Therefore, there are approximately 0.379 moles of Ca in the given sample.

7 0
3 years ago
Which selection contains elements that are NOT all in the same group?
Volgvan

Answer:

Iron, copper , calcium

Explanation:

Iron , copper and calcium are present in three different groups.

Iron is present in group eight.

Copper is present in group eleven.

Calcium is present in group two.

Sodium , potassium and rubidium are present in same group i.e. group one. These are alkali metals.

Fluorine, chlorine and bromine are present in group seventeen. These are halogens.

Argon, Krypton and xenon are present in same group i.e, group eighteen. All are these noble gases.

4 0
3 years ago
2. How many calories are needed to raise 50 g of iron from 55°C to 200°C? (c = 0.110 cal/g °C)
lord [1]

Answer:

Q = 797.5 cal

Explanation:

Given that,

Mass of iron, m = 50 g

The temperature rises from 55°C to 200°C.

We need to find the heat needed to raise the temperature. The heat raised is given by :

Q=mc\Delta T

Put all the values,

Q=50\times 0.11\times (200-55)\\\\Q=797.5\ cal

So, 797.5 calories of heat is needed.

3 0
3 years ago
. What is the main gas found in the air we breathe?
laiz [17]

Answer:

Nitrogen

Explanation:

4 0
4 years ago
Which of the following represents the ester functional group?
Komok [63]

Answer:

D. C=O

Explanation:

Esters are formed by the condensation of alcohols and acids with minus water. During the reaction, at least one -OH group is replaced by an O- alkyl group. The resulting compound is an ester and has a characteristic fruity smell. Its functional group is C=O

5 0
3 years ago
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