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Klio2033 [76]
3 years ago
9

Which statement describes a chemical reaction?

Chemistry
2 answers:
yuradex [85]3 years ago
6 0

Answer:

reactants form products when atoms are rearranged.

ELEN [110]3 years ago
4 0
The statement that describes a chemical reaction is the statement c. reactants form products when atoms are rearranged.<span> The atoms of the reactants are arranged is a specific position and number forming a determined compound. In a chemical reaction, the products are different compounds than the reactants, so the atoms have to rearrange to form these new compounds (the products).</span><span />
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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that
kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is 1.1\times 10^6 M.

HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)

This value indicates that

A. CN^- is a stronger base than ONO^-

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is ONO^-

D. The conjugate acid of CN- is HCN

Answer: A. CN^- is a stronger base than ONO^-

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When K_{p}>1; the reaction is product favoured.

When K_{p}; ; the reaction is reactant favored.

When K_{p}=1; the reaction is in equilibrium.

As, K_p>>1, the reaction will be product favoured and as it is a acid base reaction where HONO acts as acid by donating H^+ ions and CN^- acts as base by accepting H^+

Thus HONO is a strong acid thus ONO^- will be a weak conjugate base and CN^- is a strong base which has weak HCN conjugate acid.

Thus the high value of K indicates that CN^- is a stronger base than ONO^-

7 0
3 years ago
(select all that apply.) the elements most often found in organic molecules are _____.
Arturiano [62]
<span>C. Carbon. H. Hydrogen. N. Nitrogen. O. Oxygen. P. Phosphorus. <span>S. Sulfur.</span></span>
7 0
3 years ago
Read 2 more answers
What is a possible quantum number set for an electron in the 2s orbital of a beryllium (Be) atom?
Artist 52 [7]

Answer is: 2,0,0,±1/2.

1) n = 1. The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.

2) l = 0. The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.

3) ml = 0. Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.

Magnetic quantum number (ml) specifies the orientation in space of an orbital of a given energy and shape . Magnetic quantum number divides the subshell into individual orbitals which hold the electrons, there are 2l+1 orbitals in each subshell.  

4) The spin quantum number, ms, is the spin of the electron; ms = +1/2 or -1/2.

7 0
3 years ago
Which property explains why water is able to travel against gravity, from the roots of a plant to the leaves at the top of the p
gizmo_the_mogwai [7]

Answer:

Surface tension is also a property that enables water to travel against gravity.

Explanation:

Surface tension is a property of a liquid that holds the surface together and allows it to resist an external force.

7 0
3 years ago
Consider the following generic reaction for which Kp = 5.51 × 105 at 25°C:
lora16 [44]

Answer:

K_c=1.35\times 10^7

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2R_{(g)}+A_{(g)}\rightleftharpoons2Z_{(g)}

Given: Kp = 5.51\times 10^5  

Temperature =  25°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T = (25 + 273.15) K = 298.15 K  

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(2+1) = -1  

Thus, Kc is:

5.51\times 10^5= K_c\times (0.082057\times 299)^{-1}

K_c\frac{1}{24.535043}=551000

K_c=13518808.69=1.35\times 10^7

3 0
3 years ago
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