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3 years ago

The sum of the prime divisors of 2001 is a) 55, b) 56, c) 670, d) 671, e) 2001

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Answer:

Option A

Step-by-step explanation:

2001 can be divided by 3, 23, and 29 without remainders. This means that the three numbers are prime divisors of 2001.

2001/3 = 667

2001/23 = 87

2001/29 = 69

The sum of the prime divisors is 55.

3 + 23 + 29 = 55

Option A should be the correct answer.

Hope this helps.

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