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3 years ago

The sum of the prime divisors of 2001 is a) 55, b) 56, c) 670, d) 671, e) 2001

Mathematics

1 answer:

ollegr [7]3 years ago

4 0

Answer:

Option A

Step-by-step explanation:

2001 can be divided by 3, 23, and 29 without remainders. This means that the three numbers are prime divisors of 2001.

2001/3 = 667

2001/23 = 87

2001/29 = 69

The sum of the prime divisors is 55.

3 + 23 + 29 = 55

Option A should be the correct answer.

Hope this helps.

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Answer:

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Step-by-step explanation:

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2 years ago

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djyliett [7]

Answer:

$C(d) = \frac{1}{5}d + 320$

Step-by-step explanation:

Given

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$C \to cost$

So:

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Required

Express as a function

Start by calculating the slope (m)

$m = \frac{\triangle C}{\triangle d}$

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$m = \frac{24}{120}$

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Take LCM

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2 years ago

Explain and give example of binomial theorem

Ludmilka [50]

Answer:

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Step-by-step explanation:

I tried to answer it the best I could, hope this helps!

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2 years ago

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Answer:

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Step-by-step explanation:

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Hope this helps!

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vivado [14]

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3 years ago

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