find the probability of at least 3 successes in a 3 trials of a binomial experiment i which the probability of successe is 50%

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

each trial is independent so do

.5 x .5 x .5 or .5^3

.125 is the probability.

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Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360°

vodka [1.7K]

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$\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\$

$x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\$

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Stephen and five of his friends went out to eat. They decided to split the bil

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Stephen and his five friends = 6 people at the restaurant

Let's call X the amount of the bill.

so if X/6 = 13.21

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X = 79.26

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Step-by-step explanation:

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The difference of twice a number and 3 is 11

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Let's break this down:

The difference: Something's gotta be subtracted
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2n - 3 = 11

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