In a different plan for area codes, the first digit could be any number from 2 through 5, the second digit was either 2, 3, 4,

Question

2 years ago

9

or 5, and the third digit could be any number except 4, 5, or 8. With this plan, how many different area codes are possible?

1 answer:

GrogVix [38] · Answer 1 · 2022-08-05T18:04:39+03:00

3 0

Answer:

Step-by-step explanation:

First digit 2,3,4,5 = 4 different digits.

Second digit 2,3,4,5 = 4 different digits.

Third digit = 1,2,3,6,7,9 = 6 different digits.

Total number of possibilities = 4*4*6 = 96

In a different plan for area​ codes, the first digit could be any number from 2 through 5​, the second digit was either 2, 3, 4,