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lyudmila [28]
3 years ago
13

I forgot how to do it help!?

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Replace x with -3 and add

y = -x+1

y = -( x ) + 1

y = -( -3 ) + 1 .... replace x with -3

y = 3 + 1 ... two negatives cancel to make a positive

y = 4

So the number 4 goes right next to -3. This means the point (x,y) = (-3,4) is on the line. This is shown as point A on the attached image below.

------------------------

Repeat for x = -1

y = -x + 1

y = -( x ) + 1

y = -( -1) + 1 ... replace x with -1

y = 1 + 1

y = 2

So the point (-1,2) is also on the line. This is shown as point B.

-------------------------

Repeat for x = 0

y = -x + 1

y = -0 + 1 ... replace x with 0

y = 1

So (0,1) is on the line. This is point C.

-------------------------

Finally, plug in x = 4

y = -x + 1

y = -4 + 1 ... replace x with 4

y = -3

So (4,-3) is on the line, shown as point D.

-------------------------

After you have at least 2 points plotted on the coordinate grid, you would draw a straight line through those points. Note how points A,B, C, & D are all on the same straight line. The slope of this line is -1 meaning you go down 1 unit each time you move to the right 1 unit. The y intercept is 1, which is where the blue line crosses the y axis.

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For the funtion f(x)= (x+7)^5, Find f^-1 (x)
quester [9]

Answer:

The inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

Step-by-step explanation:

For the function f(x)= (x+7)^5, Find f^{-1} (x)

For finding inverse of x,

First let:

y=(x+7)^5

Now replace x with y and y with x

x=(y+7)^5

Now, solve for y

Taking 5th square root on both sides

\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7

Now, replace y with f^{-1} (x)

f^{-1} (x)=\sqrt[5]{x}+7

So, the inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

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