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lyudmila [28]
3 years ago
13

I forgot how to do it help!?

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Replace x with -3 and add

y = -x+1

y = -( x ) + 1

y = -( -3 ) + 1 .... replace x with -3

y = 3 + 1 ... two negatives cancel to make a positive

y = 4

So the number 4 goes right next to -3. This means the point (x,y) = (-3,4) is on the line. This is shown as point A on the attached image below.

------------------------

Repeat for x = -1

y = -x + 1

y = -( x ) + 1

y = -( -1) + 1 ... replace x with -1

y = 1 + 1

y = 2

So the point (-1,2) is also on the line. This is shown as point B.

-------------------------

Repeat for x = 0

y = -x + 1

y = -0 + 1 ... replace x with 0

y = 1

So (0,1) is on the line. This is point C.

-------------------------

Finally, plug in x = 4

y = -x + 1

y = -4 + 1 ... replace x with 4

y = -3

So (4,-3) is on the line, shown as point D.

-------------------------

After you have at least 2 points plotted on the coordinate grid, you would draw a straight line through those points. Note how points A,B, C, & D are all on the same straight line. The slope of this line is -1 meaning you go down 1 unit each time you move to the right 1 unit. The y intercept is 1, which is where the blue line crosses the y axis.

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Answer:

\sin\,\theta =-\frac{\sqrt{21} }{5}

\tan\,\theta =\frac{\sqrt{21} }{2}

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Step-by-step explanation:

\cos\theta =\frac{-2}{5}

As both sin\,\theta,

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In the third quadrant,

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\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

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to figure this problem out you put
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4 squared=16
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