All categories

2 years ago

Can someone help me with this

Mathematics

1 answer:

olasank [31]2 years ago

4 0

E and F are common factors. 1 goes into 2 and 24 and 2 goes i to 2 and 24.

You might be interested in

If g(x) = 2(x − 4), find the value of x if g(x) = 20

Natalka [10]

Substitute for x.
g(20)= 2(20-4)
g(20)=32.
x=32.
~god bless you!

4 0

2 years ago

Read 2 more answers

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th

Rom4ik [11]

The linear equality represented by the graph as, $\rm y > \frac{2}{3} x+3$

<h3>What is the definition of inequality?</h3>

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

The slope of the dashed line is found as;

$\rm m = \frac{y_2-y_1}{x_2-x_1} \\\\\ m = \frac{3-1}{0+3} \\\\ m= \frac{2}{3}$

The slope-intercept form is;

y=mx+c

Substitute the obtained value;

$\rm y = \frac{2}{3}x+3$

We are aware that the given line Is a dashed line, and everything to its left is shadowed.

Hence, the linear equality is represented by the graph as, $\rm y > \frac{2}{3} x+3$

To learn more about inequity, refer to brainly.com/question/20383699

#SPJ1

4 0

1 year ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

2 years ago

Describe how to draw a line that passes through the origin and has a slope of -2/3

Bas_tet [7]

Place a dot on the origin.
A line that has a slope of $\frac{-2}{3}$ goes by this formula:
$\frac{rise}{run}$
So "rise -2" and "run 3."
Rise -2 is basically go down 2, so go down 2 units from the origin. Run 3 means go right 3 units from (0, -2).
Draw a line through (3, -2) and (0, 0).

5 0

2 years ago

Brock spent $20 at the arcade. This represents 10% of the money earned by working at the pizza parlor last week. How much money

marusya05 [52]

The answer will be $200

7 0

2 years ago