Answer:
the answer is C
Step-by-step explanation:
i had a test that had this same question. Hope this Helps!!! :)
Answer:
itself was just<em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>awesome</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>had</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>game</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>friends</u></em><em><u>.</u></em>
Well as x can never actually be -1 because I'm in the denominator -1 + 1 = 0 and we cannot divide by zero. But we can look at what number it approaches and i assume that is the relative value. sometimes functions will have asymptotes and others will have holes in the graph. this one would have an asymptote going down at a rapid rate. the asymptote would go on forever getting infinitely close to -1 but never touching. So I would say since the asymptote goes down forever that the graph approaches negative infinity
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
<h3>How to evaluate a piecewise function at given values</h3>
In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:
<h3>r(- 3): </h3>
-3 ∈ (- ∞, -1]
r(- 3) = - 2 · (- 3) + 9
r (- 3) = 15
<h3>r(- 1):</h3>
-1 ∈ (- ∞, -1]
r(- 1) = - 2 · (- 1) + 9
r (- 1) = 11
<h3>r(1):</h3>
1 ∈ (-1, 5)
r(1) = 2 · 1² - 4 · 1 - 5
r (1) = - 7
<h3>r(5):</h3>
5 ∈ [5, + ∞)
r(5) = 4 · 5 - 7
r (5) = 13
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
To learn more on piecewise functions: brainly.com/question/12561612
#SPJ1
If she can drive 4180 miles in <em>two </em>weeks, it would make sense that she would drive an average of <em>half </em>that distance in <em>one </em>week. Half of 4180 is 2090, so she averaged 2090 miles each week.