Answer:
![K_{c} = [\text{C}]^{2}[\text{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctext%7BC%7D%5D%5E%7B2%7D%5B%5Ctext%7B%5BD%5D%7D)
Explanation:
The general formula for an equilibrium constant expression is
![K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cdfrac%7B%5B%5Ctext%7BProducts%7D%5D%7D%7B%5B%5Ctext%7BReactants%7D%5D%7D)
Solids and liquids are not included in the equilibrium constant expression.
Thus, for this reaction,
![K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctextbf%7BC%7D%5D%5E%7B%5Cmathbf%7B2%7D%7D%5Ctextbf%7B%5BD%5D%7D)
<span> It is important to keep the NaOH solution covered at all time because sodium hydroxide is a very good remover of Carbon dioxide from the air means sodium hydroxide absorbs the carbon dioxide from the air react with that so the concentration of your solution will also change if you uncover the NaOH.
The following reaction occurs when sodium hydroxide reacts with carbon dioxide;
</span><span>2 NaOH(aq) + CO2(g) --> Na3CO3(aq) + H2O(l) </span>
Answer:
0.2
Explanation:
1. First, figure out the molar mass of said element(s).
The molar mass of carbon is 12.0107. Whether you round this or leave it as is depends on your's and/or your teacher's personal preference.
2. Next, convert grams to moles by dividing the initial mass of carbon by the molar mass. Round if neccecary.
2.4g ÷ 12.0107g/mol = 0.2mol
Answer:
Ketone
Explanation:
According to the description of the functional group attached to the hydrocarbon - the first and last of a chain of three carbons are each single bonded to 3 hydrogen (H)atoms; the center carbon is double bonded to an oxygen atom, O - it can be deduced that the functional group is a ketone group.
A ketone is a functional group with the structure R₂-C=O, where the two R are alkyl or phenyl groups which may be the same or different. The carbon in a double covalent bond with oxygen is called the carbonyl carbon. The two R groups are bonded to the carbonyl carbon in single covalent bonds.
In the hydrocarbon in this question, the two R groups are methyl groups, CH₃ bonded to the carbonyl carbon. The name of the hydrocarbon is propanone and it is a ketone molecule.
Chemical changes occur when a substance combines with another to form a new substance, called synthesis or, alternatively, decomposes into two or more different substances.
