Answer:
0.29mol/L or 0.29moldm⁻³
Explanation:
Given parameters:
Mass of MgSO₄ = 122g
Volume of solution = 3.5L
Molarity is simply the concentration of substances in a solution.
Molarity = number of moles/ Volume
>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.
Number of moles = mass/ molar mass
Molar mass of MgSO₄:
Atomic masses: Mg = 24g
S = 32g
O = 16g
Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol
= (24 + 32 + 64)g/mol
= 120g/mol
Number of moles = 122/120 = 1.02mol
>>>> From the given number of moles we can evaluate the Molarity using this equation:
Molarity = number of moles/ Volume
Molarity of MgSO₄ = 1.02mol/3.5L
= 0.29mol/L
IL = 1dm³
The Molarity of MgSO₄ = 0.29moldm⁻³
Answer:
Option 6 ) Neutralization
Explanation:
For this case, the missing coefficient would be a "6" before the H₂O, within final products (right side of the equiation), hence, the final reaction should be:
2H₃PO₄ + 3Ba(OH)₂ ------> Ba₃(PO₄)₂ + 6H₂O
You should have in mind that the amount of atoms at each side of the chemical equation should be the same, so as to comply with the principle of mass conservation. If you add "6" on the left side of the H₂O, the equation will be balanced (for each side, lef and right, you will have: 12H, 2P, 14O and 3Ba)
Lastly, this is a chemical neutralization reaction, where an acid (H₃PO₄) is reacting with a base (Ba(OH)₂) in order to finally obtain a neutral salt (Ba₃(PO₄)₂) and water (H₂O)
Answer:potassium is more reactive than Mg because both lie in the same group and the element potassium has more electropositivity than magnesium
Explanation:
I hope it will help you
Answer:
Mass = 17.12 g
Explanation:
Given data:
Mass of Al = 3.90 g
Mass of H₂SO₄ = 13.65
Mass of aluminium sulfate = ?
Solution:
Chemical equation:
3H₂SO₄ + 2Al → Al₂(SO₄)₃ + 3H₂
Now we will calculate the number of moles of each reactant.
Moles of H₂SO₄:
Number of moles = mass/ molar mass
Number of moles = 13.65 g/ 98.079 g/mol
Number of moles = 0.14 mol
Moles of Al:
Number of moles = mass/ molar mass
Number of moles = 3.90 g/ 27 g/mol
Number of moles = 0.14 mol
Now we will compare the moles of aluminium sulfate with sulfuric acid and aluminium.
H₂SO₄ : Al₂(SO₄)₃
3 : 1
0.14 : 1/3×0.14 = 0.05
Al : Al₂(SO₄)₃
2 : 1
0.14 : 1/2×0.14 = 0.07
The number of moles of aluminium sulfate produced by sulfuric acid are less so it will limiting reactant and limit the amount of aluminium sulfate.
Mass of aluminium sulfate:
Mass = number of moles × molar mass
Mass = 0.05 mol × 342.15 g/mol
Mass = 17.12 g
Answer:
The pitch of the sound a person makes is determined by several factors, including the size and tension of his or her vocal cords.
Explanation: