Answer:
10
Explanation:
num1=3 and num2=2
num3=myproc(num1)+myproc(num2)
myproc(num1) results 6
myproc(num2) results 4
when we add both e get 10
Answer:
Hotkey commands
Explanation:
It would be easier and more efficient in the long run to use hotkeys.
Answer:
#include <iostream>
#include <array>
using namespace std;
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++)
if (toupper(str[i]) != toupper(str[length - 1 - i]))
return false;
return true;
}
int main()
{
array<string, 6> tests = { "madam", "abba", "22", "67876", "444244", "trymEuemYRT" };
for (auto test : tests) {
cout << test << " is " << (isPalindrome(test) ? "" : "NOT ") << "a palindrome.\n";
}
}
Explanation:
The toupper() addition forces characters to uppercase, thereby making the comparison case insensitive.
