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Basile [38]
3 years ago
6

What can handle work that is hard on a person and could cause repetitive injuries?

Computers and Technology
1 answer:
Yuki888 [10]3 years ago
4 0

The robot which can handle work that is hard on a person and could cause repetitive injuries is a: Cobot.

Artificial intelligence (AI) is also referred to as machine learning and it can be defined as a branch of computer science which typically involves the process of using algorithms to build a smart computer-controlled robot or machine that is capable of performing and handling tasks that are exclusively designed to be performed by humans or with human intelligence.

A cobot is an intelligent robot that is designed and developed to perform and handle work that may be too hard (difficult) and hazardous for a person or could cause repetitive injuries to him or her.

Read more: brainly.com/question/21656851

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Write a program that accepts a phrase of unspecified length on the command line. For example: prompt% letter print Operating Sys
Sedaia [141]

Answer:

Check the explanation

Explanation:

#define _MULTI_THREADED

#include <pthread.h>

#include <stdio.h>

#include <errno.h>

#define           THREADS          2

int               i=1,j,k,l;

int argcG;

char *argvG[1000];

void *threadfunc(void *parm)

{

int *num;

num=(int*)parm;

while(1)

   {

   if(i>=argcG)

   break;

   if(*num ==1)

   if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

    if(*num ==2)

   if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

   sched_yield();

   }

return NULL;

}

int main(int argc, char *argv[])

{

pthread_t            threadid[THREADS];

int                  rc=0;

int                  loop=0;

int arr[2]={1,2};

argcG=argc;

for(rc=0;rc<argc;rc++)

argvG[rc]=argv[rc];

printf("Creating %d threads\n", THREADS);

for (loop=0; loop<THREADS; ++loop) {

     rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);

}

for (loop=0; loop<THREADS; ++loop) {

   rc = pthread_join(threadid[loop], NULL);

}

printf("Main completed\n");

return 0;

}

The below attached image is a sample output

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3 years ago
Please help What two Boolean operators can you use to narrow your search results?
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Answer:

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7 0
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Answer and Explanation:

In C programming language:

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e=getchar();

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}

int main(int argc, char *argv[]) {

int d;

int f;

int g;

fun();

printf("%d%d%d", d, f, g);

}

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