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3 years ago

Determine the 30th term of the sequence -10 -15 -20

Mathematics

2 answers:

shtirl [24]3 years ago

7 0

The 30th term is -155

creativ13 [48]3 years ago

3 0

190. Count it out on your fingers, starting with -10,-15, and -20. Then count out both hands.

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Solve * x + 12/2= 3(x + 7)

zheka24 [161]

Step-by-step explanation:

x+6=3x+21

2x=-15

x=-7.50

6 0

3 years ago

Read 2 more answers

Simplify the expression. (7x + 3) + (4x - 1) - (2x + 4)

Crazy boy [7]

Answer:

9x -2

Step-by-step explanation:

(7x + 3) + (4x - 1) - (2x + 4)

Distribute the minus sign

(7x + 3) + (4x - 1) - 2x - 4

Combine like terms

7x+4x-2x +3 -1-4

9x -2

3 0

3 years ago

Which of the following steps would you perform to the system of equations below so that the equations have opposite y-coefficien

denis23 [38]

I think B not 100%shure ,you could prob go ask this on yahoo and get a bit more help ;) sorry I couldent help more

3 0

3 years ago

Read 2 more answers

Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0

Rus_ich [418]

The Solution:

Given the equation of a line:

$6x-y-4=0$

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

$\begin{gathered} \text{ Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}$

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

$\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\ \\ Slope=m_1=6 \end{gathered}$

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

$\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\ \end{gathered}$

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

$y-y_1=m_2(x-x_1)$

In this case,

$\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}$

Substituting these values in the formula, we get the required equation is:

$\begin{gathered} y--1=\frac{-1}{6}(x--12) \\ \\ y+1=-\frac{1}{6}(x+12) \end{gathered}$

Cross multiplying, we get

$\begin{gathered} 6y+6=-x-12 \\ \\ 6y+x+6+12=0 \\ \\ 6y+x+18=0 \end{gathered}$

Therefore, the correct answer is:

$6y+x+18=0$

5 0

1 year ago

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and

storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of proportionality, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

$\frac{6.4^{2}}{156} k = 800$

$k=\frac{800.156}{96}$

k = 1300

For the similar beam:

$\frac{8.7^{2}}{L}1300=1300$

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0

3 years ago